关于二项式的一个猜想

A Conjecture Of Binomial

对二项式的一个猜想,对所有的自然数n均有:(a+b)2n+1=a2n+1+b2n+1+2n+1ab(a+b)(a2+ab+b2)n-1作了进一步的探讨,并且得到不等式(2),(3).

In this article we discussed a conjecture(*) of Binomial and obtained two inequalities(2),(3).The conjecture is that there is(a+b)2n+1=a2n+1+b2n+1+2n+1ab(a+b)(a2+ab+b2)n-1 for every natural number n.