摘要
设Q={f(z):f(z)=z-an+1zn+1-sum from k=n+2 to ∞(akzk)},这里an+1=(c(n+2))/((n+1)(n+3)),ak≥0,sum from k=n+2 to ∞((k(k+2))/(k+1)ak)≤1-c,0≤c≤1,n∈N,并且f(z)在单位圆盘Δ={z:|z|<1}内解析,得到函数族Q的极值点与支撑点.
Let Q={f(z):f(z)=z-an+1zn+1-sum from k=n+2 to ∞(akzk)},where an+1=c(n+2)(n+1)(n+3),ak≥0,an+1=(c(n+2))/((n+1)(n+3)),ak≥0,sum from k=n+2 to ∞((k(k+2))/(k+1)ak)≤1-c,0≤c≤1,n∈N and f(z)was analytic in the unit open disk,the extreme points and support points of the class Q were obtained.
出处
《湖北大学学报(自然科学版)》
CAS
2012年第2期215-217,230,共4页
Journal of Hubei University:Natural Science
基金
四川省成都理工大学工程技术学院科研发展基金(C122010003)资助
关键词
单叶函数
解析函数
线性泛函
极值点
支撑点
univalent function
analytic function
linear functional
extreme points
support points