摘要
运用收敛级数逐项求导的方法求出 n为 1与 2时的级数和 ,并给出引理及证明。用递推法逐个求出该级数的和。
The sum of the unlcinited progression can be got when N equals 1 & 2 with evaluating the derivative step by step & confirmation convergence,and then the reason approach & confirmation are introduced.Finally the sum of each unlimited progression is got with the method of recumence.
出处
《唐山学院学报》
2002年第3期59-60,共2页
Journal of Tangshan University
关键词
无穷级数
达朗贝尔判别法
逐项求导
引理
递推法
original distance
unlimited progression
evaluate the derivative step by step
the reason approach
the method of recumence
