摘要
1≤j≤nx<sup>1</sup>=x°+ap△y=（2.999,0.433,1.000,2.567,0.001.15.866）<sup>T</sup>y<sup>1</sup>=y°+aD△z=（1.015,1.098,-1.293,0.082）<sup>T</sup>z<sup>1</sup>=z°+aD△x=（0.001,2.209,1.721,0.373,17.374,0.082）<sup>T</sup>d=（x<sup>1</sup>）<sup>T<sub>z</sub>l</sup>=4.940,继续迭代.迭代2:由于以下的计算都是重复送代1的计算过程,故下面只列出每次迭代计算的有关参数和最后结果.
