求a^(n1)^(n2)·(n1)的个位数的一般方法

A Genesality of Finding umber in the First Number Place of a^(n1)^(n2)·(n1)

在许多关于整数整除性的小册子中都谈到了求形如(?)的个位数的问题,但都只就某一个具体的数来谈它的求法,没有形成一般方法。本文给出这个问题的一般求法,

In many pamphlets recently published referring to the exact dividing of an in teger such as the number in the first number place if an1,n2…n1,they only tell us themethod of performing a certain number, not the generality Here, the paper gives the genrality of solving such prolems