摘要
由对二甲氨基苯甲醛(A)和N,N′-二甲基苯胺(B)在盐酸存在下与尿素反应,合成题示化合物。研究了它的反应机理。结果表明,在强酸存在下,该反应是分两步进行的。首先是A和B缩合形成米氏醇(4,4′-二甲氨基二苯甲醇)中间物,然后再与尿素作用得到尿素衍生物。同时证明,该类取代苯甲醛与取代芳胺,在强酸介质中与尿素作用合成相应的尿素衍生物,都是按上述两步机理进行的。
The title compound was synthesized by the condensation of p-dimethylaminobenzaldehyde(A), N,N-dimethylaniline(B) with urea in the present of conc. HCI. The resuits showed clearly that the synthetic machanism appears to be a two-step process, Viz. (1) dimethylaminobenzohydrol as Michler's Hydrol is formed by the aldol condensation between A and B and (2) Elimination of water between Michler's Hydrol as intermediate and urea proceeds to form the urea derivative. The reaction mechanisms of other urea derivatives formed by the condensation of substitute arylaldehyde, arylaniline with urea in strong acidic media are the same as the two-step mechanism mentioned above.
关键词
热敏染料
尿素
紫内酯
结晶
reaction mechanism
Michler's Hydrol
p-dimethylaminobenzaldehyde
N
N'bis{bis[(p-dimethylamino)phenyl]methyl}urea
urea derivatives
