Pd_2X_2（dpm）_2（X＝NCO~－，CH_3CO_2~－，SCN~－，

NMR Study of the Reaction of Pd_2X_2(dpm)_2 (X=NCO￣-,CH_3CO_2￣-,SCN￣-,NO_2￣-;dpm=Ph_2PCH_2PPh_2) Complexes with H_2S

采用ＮＭＲ方法考察了室温和低温（－７８～－６０℃）下Ｐｄ２Ｘ２（ｄｐｍ）２（Ｘ＝ＮＣＯ－，ＣＨ３ＣＯ，ＳＣＮ－和ＮＯ，ｄｐｍ＝Ｐｈ２ＰＣＨ２ＰＰｈ２）与Ｈ２Ｓ在ＣＤ２Ｃｌ２或ＣＤＣｌ３中的反应。结果表明，在Ｘ＝ＮＣＯ－和ＣＨ３ＣＯ的情况下，Ｈ２Ｓ优先与这些Ｐｄ配合物的阴离子作用生成相应的共轭酸ＨＸ和Ｐｄ２（ＳＨ）２（ｄｐｍ）２，后者在Ｈ２Ｓ存在下又进一步转化为Ｐｄ２（ＳＨ）２（ｄｐｍ）２（μ－Ｓ）；当Ｘ＝ＳＣＮ－和ＮＯ时，反应则生成结构可能为［Ｐｄ２（Ｈ）（ＳＨ）（μ－ＳＨ）（ｄｐｍ）２］＋的双核Ｐｄ配合物。

The reactions of Pd2X2(dpm)2(X=NCO-,CH3CO,SCN-and NO;dpm = Ph2PCH2PPh2)with H2S in CD2Cl2 or CDCl3 were studied by NMR at room and low temperature (-78--60 ℃).In the case of X = NCO-and CH3CO, H2S at first reacted with the anions of the palladium complexes and generated HX and Pd2(SH)2(dpm)_2 that was subsequently converted to Pd2(SH)2(dpm)2(μ-S)in the presence of excess amount of H2S.In the case of X=SCN- and NO,the reactions resulted in the formation of a dinuclear palladium complex with a possible structure of[Pd2(H)(SH)(μ-SH)(dpm)2]+.