配合物[Pd(phen)Cl_2]与腺嘌呤的键合作用研究

Study on Linkage Action of Complex [Pd(phen)Cl_2] and Adenine

合成并表征了固体三元配合物[Pd(phen)Cl2]1.以1和DNA的组成小分子腺嘌呤(ade)反应,获得双核配合物单晶[Pd2(phen)2(ade)2]Cl2?4.5H2O (2). 配合物2为正交晶系, 空间群为Pnma, 晶胞参数a=2.1709(9) nm, b=1.4378(6) nm,c=1.2274(5) nm, α=β=γ=90°, V=3.8311(3) nm3, Dc=1.729 g/cm3, Z=4, F(000)=2004, R1=0.0766, wR2=0.1526. phen配体以两个氮原子与钯(II)离子配位, 按生物学原子规范标号, ade 以N(3), N(9)原子与钯(II)离子桥联配位, 形成双核混配型配合物.

Solid ternary complex [Pd(phen)Cl-2] (1) was synthesized and characterized. Complex 1 was reacted with adenine (ade) of DNA and single crystal of binuclear complex [Pd-2(phen)(2)(ade)(2)]Cl(2)center dot 4.5H(2)O (2) was obtained. Complex 2 belongs to orthorhombic system with space group Pnma, a = 2.1709(9) NM, b = 1.4378(6) nm, c = 1.2274(5) nm, a = beta = gamma = 90 degrees, V = 3.8311(3) nm(3), D-c = 1.729 g/cm(3), Z = 4, F(000) = 2004, R-1 = 0.0766, wR(2) = 0.1526. Two nitrogen atoms of phen and N(3), N(9) of ade coordinated with Pd(H).