EuCl_3-CdCl_2-HCl-H_2O(25℃)的相平衡及其固相化合物

Phase Equilibrium of the System EuCl_3-CdCl_2-HCl-H_2O at 25 ℃ and Characterization of New Compounds

测定了四元体系EuCl3-CdCl2-HCl-H2O(25℃)的相平衡溶度数据,绘制了相应的溶度图。该四元体系是复杂体系且有2个新物相化合物9CdCl·2EuCl·322H2O和4CdCl·2EuCl·314H2O生成。2个新物相化合物用XRD及TG-DTG和荧光光谱进行了研究。结果表明,新物相化合物均属单斜晶系;在240nm波长光的激发下,化合物9CdCl·2EuCl·322H2O和4CdCl2·EuCl·314H2O分别在390nm、385nm处有较强的荧光发射峰;9CdCl·2EuCl·322H2O通过2步失去其结晶水,4CdCl2·EuCl3·14H2O通过4步失去其结晶水。

The equilibrium solubilities of the quaternary system EuCl3-CdCl2-HCl-H2O was determined at 25 ℃ and the corresponding equilibrium diagram was constructed. The systems is complicated with two new compounds 9CdCl2·EuCl3·22H2O and 4CdCl2·EuCl3·14H2O which have not yet been reported in literatures. The two new compounds have been characterized by XRD, TC-DTG and fluorescence spectrophotometer. Results show that the two compounds belong to monoclinic system, fluorescence spectrum exhibit at 390 nm （9CdCl2·EuCl3·22H2O） and 385 nm （4CDCl2·EuCl3· 14H2O） excited at 240 nm, and 9CdCl2： EuCl3·22H2O loses its crystal water by two steps at 50 ℃ to 241 ℃, 4CdCl2·EuCl3· 14H2O loses its crystal water by four at 42 ℃ to 332 ℃.