摘要
六甲基二硅胺烷(HMDS)在KF/苄基三乙基氯化铵(TEBA)体系中.与不同的芳香醛反应均可以获得三芳基缩二胺.后者经高猛酸钾、N-澳代丁二酰亚胺(NBS)或者2,3-二氯-5,6-二氰基对苯醌(DDQ)氧化,都能得到三芳基取代均三嗪化合物.本文还对反应机理进行了探讨.
In the KF/TEBA system,all reactions of different aromatic aldehydes with hexamethyldisilazane (HMDS) will result in formation of N, N'-diaryl- methylenearylmethane diamines, and all these products will turn to s-triazines through oxidation with KMnO4, NBS or DDQ. The mechanism of the reaction has been discussed.
出处
《复旦学报(自然科学版)》
CSCD
北大核心
1996年第3期284-288,共5页
Journal of Fudan University:Natural Science