矩阵环的一类Armendariz子环

An Armendariz Subring in Matrix Ring

设R是Reduced环,α1,α2是R的相容自同态,T(R;α,β)是由α1和α2决定的一类特殊的R上的三阶矩阵子环。证明了T(R;α,β)是Armendariz环。

Suppose R is Reduced ring, α1, α2 is R＇s consistent endomorphism, T（ R;α,β ） is special matrix subring determined by α1 and α2. This article proves that T （R;α,β） is Armendariz ring.