整函数涉及分担值的惟一性

Uniqueness of Entire Functions Concerning Sharing Value

采用分担值的思想,考虑了整函数分担一个值的惟一性问题,主要证明了:设f(z)和g(z)是2个非常数整函数,正整数k,n满足n≥2k+11。若[fn(f2-1)](k)和[gn(g2-1)](k)以1为CM公共值,则f(z)≡g(z)。

The uniqueness of entire functions that share one value was studied, and the following result was proved ： For two non-constant entire functionsf（z） and g（z） , If [f^n（f^2-1）]^（k） and [g^n（g^2-1）]^（k） share 1 as CM, where k and n are two positire integers satisfying n≥k ＋ 11, then f（z） ≡g（z）.