摘要
采用电-Fenton法对含苯酚废水进行处理,以石墨为阴极、铁为阳极,并向阴极不断通入空气,电解过程产生的H2O2与阳极溶解的Fe2+形成Fenton试剂,Fenton试剂在电解过程中产生大量活性羟基自由基,能够很好地氧化降解废水中的苯酚。实验结果表明:影响苯酚去除率的因素主次顺序为pH值、电解质浓度、电解电压、电解时间、进水苯酚浓度。单因素分析得出电-Fenton法处理苯酚模拟废水的最优反应条件:pH值控制在2左右,反应时间为60 min,电解电压选10 V,Na2SO4的浓度为30 g/L,进水苯酚浓度为150 mg/L。在最优条件下苯酚的去除率为82%。
In this paper the treatment of phenol wastewater E-Fenton reagent was studied. The electrobath was made up of iron anode and graphite cathode, meanwhile the air blew the cathode. In the process of electrifying, H2O2 and Fe^2+ composed of E-Fenton reagent were produced. E-Fenton reagent having amount of active OH degraded the phenol obviously. The experiment proved the order of factors affecting the removal rate is. pH, concentration of Na2SO4, voltage, reaction time, and concentration of phenol. The optimum operation parameters were determined by single factor analysis as follows: under the room temperature, the pH is 2, the reaction time is 60mins, the voltage is 10 V, the concentration of Na2SO4is30 g/L, and concentration of phenol is 150 mg/L. Under the optimum reaction conditions, the removal rate of phenol is 82%.
出处
《安全与环境工程》
CAS
2008年第1期62-65,共4页
Safety and Environmental Engineering