摘要
通过在完全图K4的某一条边上增加2个顶点得到一个六阶图F.分别连结F六个顶点与其他n个顶点得到一类特殊的图Hn.证明Hn的交叉数为Z(6,n)+n并由此确定且证明F×Sn的交叉数为Z(6,n)+2n.
The crossing number of Cartesian products of the graph order 6 and star, presently, was proved only for that of several graphs order 6 which are few edges and star. We add two vertices to an edge of K4 to obtain a graph F which is order 6. By connecting the 6 vertices of graph F to other n vertices will obtain a special family of graph denoted by Hn. In this paper, we proved that the crossing number of Hn is Z(6, n)+n and thereout we attested the crossing number of F×Sn is Z(6, n)+2n.
出处
《湖南文理学院学报(自然科学版)》
CAS
2008年第1期16-19,共4页
Journal of Hunan University of Arts and Science(Science and Technology)
基金
国家自然科学基金资助项目(10771062)
教育部"新世纪优秀人才支持计划"项目
关键词
图
画法
交叉数
星
笛卡儿积
Graph
Drawing
Crossing number
Star
Cartesian products