摘要
N-苯甲酰苯丙氨酸(BpheO)与Cu(phen)Cl2发生取代反应,生成了铜配合扬[Cu(BpheO)2(phen)]·H2O。晶体属单斜晶系,C2/C空间群。晶胞参数为:a=5.330(1),b=24.502(2),c=28.839(2),β=91.95(1)°,V=3764.1(8)3,Z=4,F(000)=1660,Dc=1.409g/cm3,μ=0.639mm-1。Cu与2个BpheO配体的羧基O原子及phen分子的2个N原子形成4配位的平面四边形结构。经元素分析,IR、ESR、UV、TG-DTA及磁性测定,对配合物的性质进行了研究。
Cu(phen)Cl 2 was substituted by N benzoylphenylalanine (BpheO) in water resulting in the copper(Ⅱ) complex [Cu(BpheO) 2(phen)]·H 2O.Crystal of the complex belongs to monoclinic system with space group C2/C, a=5.330(1),b=24.502(2),c=28.839(2),β=91.95(1)°,V=3764.1(8) 3,Z=4,F(000)=1660. The Cu atom is four coordinated with a square planar structure.The complex are characterized by elemental analysis,IR,ESR,UV Vis,TG DTA and magnetic moments.
出处
《化学研究与应用》
CAS
CSCD
1998年第1期49-53,共5页
Chemical Research and Application