免疫复合物共振散射光谱法测定人血纤维蛋白原

A Simple and Sensitive Immune Resonance Scattering Spectral Assay for Determination of Fibrinogen

在pH=6.2的Na2HPO4-NaH2PO4缓冲溶液中,羊抗人纤维蛋白原血清与纤维蛋白原（Fg）发生特异性结合,产生抗体抗原免疫复合物微粒,导致体系在340 nm处的共振散射峰增强。当纤维蛋白原质量浓度在1.33×10^-7～5.33×10^-6g/mL范围内,随着纤维蛋白原浓度c的增加340 nm处的共振散射强度线性增强,回归方程为ΔI340 nm=12.17c＋3.35,相关系数为0.998 6,其检出限（3σ）为2.8×10^-8g/mL Fg。考察了18种共存物质的干扰。结果表明,方法具有较高的选择性。方法用于定量分析人血浆中的纤维蛋白原,相对标准偏差在2.2%～2.3%之间,测定结果与人体正常血浆中纤维蛋白原含量基本一致。

In a pH 6.2 Na2HPO4-NaH2PO4 buffer solution,the immune reaction of goat anti-human fibrinogen serum and human fibrinogen（Fg） forms immune complex particles that exhibit a stronger resonance scattering peak at 340 nm.The resonance scattering intensity at 340 nm was enhanced with the increase of concentration of Fg.There is a linear relation in resonance scattering intensity ΔI340 nm to the Fg concentration c in a range of 1.33×10^-7~5.33×10^-6 g/mL.The regressed linear equation is ΔI340 nm=12.17c＋3.35,the relation coefficient is 0.998 6.The detection limit（3σ） is achieved at 2.8×10^-8 g/mL Fg.Influence of 18 substances on the determination was examined.Results indicate that this assay has a good selectivity.The proposed method was applied to the determination of Fg in plasma,with a relative standard deviation of 2.2%~2.3%.The result is in agreement with the Fg content in normal plasma.