双酚A双(二甲苯基磷酸酯)阻燃剂的合成

Synthesis of Bisphenol-A Bis(Dimethylphenyl Phosphate) Flame Retardant

利用三氯氧磷、双酚A、苯酚与甲酚反应制得化合物双酚A双(二甲苯基磷酸酯)。采用单因素法分别对物料比、反应温度、催化剂进行讨论,确定了适宜的工艺条件:n(三氯氧磷)∶n(双酚A)∶n(苯酚)∶n(甲酚)=3∶1∶2∶4.05;第1步反应温度为50℃,反应时间为8 h;第2步反应温度为140℃,反应时间为5 h;以AlCl3为催化剂,用量为双酚A总质量的1.5%,产品收率达到87.4%。通过FT-IR对化合物的结构进行了表征,产品质量达到国外同类产品指标;在塑料中添加该化合物,对其阻燃性能进行测试,结果表明这是一种较好的阻燃剂。

Bisphenol-A bis（ dimethylphenyl phosphate） was synthesized from phosphorus oxychloride bisphenol-A phenol and methylphenol. The effects of process parameters, such as molar ratio, reaction temperature and catalyst on the yield were respectively studied. The suitable synthesis conditions were defined as follows： the molar ratio of phosphorus oxychloride,bisphenol-A, phenol and methylphenol： 3 ： 1 ： 2 ： 4.05. In the first step, the reaction temperature was 50 ℃, and the reaction time was 8 hours. In the second step, the reaction temperature was 140 ℃, and the reaction time was 5 hours. AlCl3 was the best catalyst, and its dosage was 1.5% of the amount of all bisphenol-A. The yield reached 87.4%. The structure of the product was defined by FT-IR. The quality of the product can reach the indexes of the oversea product. The flame retardance was tested in different plastic product. It is shown showed that bisphenol-A bis（dimethylphenyl phosphate） was a good flame retardant.