摘要
对任意给定的正整数k≥2及任意正整数n,定义n的Smarandachek次补数ak(n)为最小的正整数,使得nak(n)为一个完全k次方幂,即ak(n)=min{u:u.n=mk;u,m∈N},其中N为所有正整数之集合.利用解析方法研究了级数sum from n=1 to +∞ 1/(nak(n))s的敛散性,并给出一个有趣的恒等式.
For any positive integer k≥2 and any positive integer n,we call ak (n) as the Smarandache k-th power complement number of n,if ak(n) is the smallest positive integer such that nak(n) is a perfect k-th power number. That is,ak (n )=min {u:u . n=mk;u,m ∈ N}. The main purpose of this paper is to study the convergent property of the series ^↑∞∑n 1/(nak(n)^5 using the analytic method, and give an interesting identity.
出处
《内蒙古师范大学学报(自然科学汉文版)》
CAS
2009年第4期397-399,402,共4页
Journal of Inner Mongolia Normal University(Natural Science Edition)
基金
国家自然科学基金资助项目(10671155)
关键词
k次补数
无穷级数
恒等式
k-th power complement number
infinite series
identity