溶剂萃取时三元配合物的最大分布系数

The Maximum Distribution Coefficient of Ternary Coordination Compound in Solvent Extraction

从理论上推导出溶剂萃取时有机相中三元配合物最大分布系数的计算公式,如常见的MA2-MAB-MB2三元配合物体系,当满足lgλMA2-12(lgr1+lgr2)>2l,gλMB2-12(lgr1+lgr2)>2时,在[[BA]]=姨rr21处,有机相中三元配合物MAB有最大分布系数11+2姨r1r2,式中λMA2、λMB2和λMAB分别为被萃取二元和三元配合物在有机相和水相的分配比,而r1=λλMMAA2BββMMAA2B r,2=λλMMBA2BββMMAB2B。

Equations for calculating the maximum distribution coefficient of ternary coordination compound in solvent extraction was deduced in this paper. For ordinary ternary coordination compound system： MA2-MAB-MB2,when meet lgλMA2/1/2（lgr1＋lrg2）〉2,lgλMRn-1/2（lgr1＋lgr2）〉2,the maximum distribution coefficient of ternary coordination MAB is 1/1＋2√r1r2 at [A]/[B]=√r2/r1,where λMa2 ,λMB2and λMAB are distribution ratios between organic and water phases of extractable binary and ternary coordination compounds, and r1=λMA2β2MA2/λMABβMAB,R2= λMA2βMB2/λMABβMaB