摘要
利用递归数列、同余及Pell方程解的性质证明了丢番图方程x 3+1=114y2仅有整数解(-1,0).
By using of the recurrent sequence,congruence and some properties of the solutions to Pell equation,obtained the conclusion that the Diophantine equation x3+1=114y2 has only integer solution(x,y)=(-1,0).
出处
《高师理科学刊》
2010年第6期20-21,共2页
Journal of Science of Teachers'College and University