Cu^(2+)/Na_2S_2O_8体系中自由基的研究

Study on Radicals in Cu^(2+)/Na_2S_2O_8 System

利用自由基与乙醇和叔丁醇之间反应速率差异,研究在不同条件下Cu^(2+)/Na_2S_2O_8体系中产生自由基的状况。实验研究表明:Na_2S_2O_8体系会产生·OH和SO_4^(-·),由于Cu^(2+)的催化作用,使用Cu^(2+)/Na_2S_2O_8体系比单独使用Na_2S_2O_8能产生更多的自由基·OH和SO_4^(-·)。研究还发现:pH值降低能促进Na_2S_2O_8分解产生自由基,但是会抑制SO_4^(-·)转化为·OH;温度升高,Na_2S_2O_8分解产生的·OH和SO_4^(-·)均增加。

The different rate for radicals reacting with ethanol and tert-butyl alcohol, has been used to study the radical in the Cu^2＋/Na2S2O8 system. The experiment results shows that .OH and SO4- has been produced in the Cu^2＋/Na2S2O8 system for the catalytic effect of Cu2＋,which is more than in Na2S2O8 system. It indicates that lower pH and rising temperature will enhance Na2S2O8 to transform into ·OH and SO4-. It also indicates that lower pH will restrict SO4- to turn to be ·OH.