康普顿散射中的‘反冲电子’

An Analysis of 'Recoil Electron' in Compton Scattering

文章对康普顿散射后电子的状态进行讨论。依据散射电子所获得的能量分析散射后电子所处的状态,并按相对论效应和非相对论效应分别得到散射电子的速度表达式。根据电子获得的能量,讨论了散射电子的可能状态有:当所获得的能量为零时,电子保持原状态;当cosθ>1-(h v0E if-mE0ifc)2hv0时,电子保持原态并电离出获得的能量;当cosθ=1-(h v0E if-mE0ifc)2 hv0时,电子发生跃迁;当cosθ<1-(h v0E if-mE0ifc)2 hv0,根据量子力学中的选择定则,电子将保持原态并辐射出所获能量;当cosθ<1-(h v0 W-m0Wc)2hv0,电子电离并反冲出原子。

The state of the scattered electron in Compton scattering was discussed in this article.The final state of the scattered electron was analyzed according to its acquired energy in the Compton scattering.The expressions of velocity of the scattering electron have been deduced under the relativistic or non-relativistic approximations respectively.And then according to electron acquired energy in the Compton scattering,the possible state of the electron was described： when the scattered angle was zero,i.e.the acquired energy was zero,the electron would keep initial state;when cos θ〉1-Eifm0c2（hv0-Eif）hv0,the acquired energy would be radiated out and the electron would keep initial state;when cos θ=1-Eifm0c2（hv0-Eif）hv0,the electron would occur transition;when cos θ〈1-Eifm0c2（hv0-Eif）hv0,the acquired energy would be radiated out and the electron would keep initial state according to the selection rules in Quantum mechanics;when cos θ〈1-Wm0c2（hv0-W）hv0,the electron would be ionized and became a recoil electron.