含盐条件下偶氮染料兼厌氧性生物的降解性能

Facultative anaerobic biodegradation performance of azo dyestuff under salt-containing condition

研究活性染料与不同浓度葡萄糖共基质条件下的兼厌氧性生物降解性能和K-2BP在不同盐浓度条件下的兼厌氧性生物降解性能.选择K-2BP作为目标污染物进行静态反应器生物降解实验.结果表明,兼厌氧性微生物在只有K-2BP作为基质时对染料的降解率较低,葡萄糖存在时,能提高兼厌氧性生物对染料的降解能力;葡萄糖为800mg/L时6h染料降解率为64.1%,而葡萄糖浓度为1 000mg/L时,不利于染料降解,6h染料降解率为46%,与不投加葡萄糖情况的降解率接近.葡萄糖浓度为800mg/L,盐浓度分别为2g/L,5g/L,10g/L和20g/L,其一级降解动力常数分别为0.105 78mg/L.h,0.049 47mg/L.h,0.028 69mg/L.h,0.022 75mg/L.h;半衰期分别为6.99h,14.15h,22.55h,30.21h.随盐浓度梯度升高,染料的兼厌氧性降解动力学常数逐渐降低,高盐浓度会抑制兼厌氧性微生物对染料的降解.

The facultative anaerobic biodegradation performance of reactive dyestuffs is studied by using different concentrations glucose.And based on this conclusion,the facultative anaerobic biodegradation performance of K-2BP under different salt-containing condition is investigated by static test reactor.The results indicate that facultative anaerobic microorganisms has lower degradation rate when only K-2BP is used as the substrate,and the degradation rate would be increased under the existence of the glucose.The glucose concentration is 800 mg/L,while the degradation rate of K-2BP is 64.1% in 6h.However,it is detrimental to dye′s biodegradation when the glucose concentration is up to 1 000 mg/L,the degradation rate is only about 46%,that is similar to the condition of non-glucose.On the premise of glucose concentration 800 mg/L,when the salt concentrations are 2 g/L,5 g/L,10 g/L and 20 g/L respectively,the first-order kinetics constants are 0.10578 mg/L·h,0.04947 mg/L·h,0.028 69mg/L·h and 0.022 75mg/L·h respectively.And the half-lives are 6.99h,14.15h,22.55h and 30.21h respectively.The reaction rate constants is decreased gradually with the salt concentrations＇ increase,which is showed that high salt concentration can restrain the facultative anaerobic microorganisms′ degradation of K-2BP.