摘要
基于全对称群的Dirac方程,研究当存在核场时的正电子能级及其与核场的关系,即计算在分子OH,SH,SeH和TeH的核场下的正电子能级.这时正电子的能量约为e+=-1.022MeV.对于低能级,当核场强增大时,其能量有所升高,而对较高能级,核场强增大时,其能量无明显变化.正负电子的湮没过程为三光子湮没过程(the three-photon annihilation).而当生成e+-e-束缚系统,即正电子原子(positronium)时,为3S态,即正态的正电子原子(orthopositronium),为激发态,这是由电荷宇称守恒所确定的.
The present work devotes to the energy levels of positron under molecules XH(X = O,S,Se and Te)and the relations with nuclear field using Dirac equation based on the full symmetry group.Under these nuclear fields,the energy of positron is about e + =-1.022 MeV.For the lower energy level,the energy of positron is increased with nuclear field;for the higher energy level,the energy of positron is nearly invariant with nuclear field.In this case,it is the three-photon annihilation.The formation of the positronium is in orthopositronium 3 S,excited state,followed the conservation of charge parity.
出处
《物理学报》
SCIE
EI
CAS
CSCD
北大核心
2011年第4期24-29,共6页
Acta Physica Sinica