四元体系RbBr-CeBr_3-HBr(13.90%)-H_2O(25℃)的相平衡

Study on phase equilibrium in the quaternary system RbBr-CeBr_3-HBr(13.90%)-H_2O at 25℃

测定了四元体系RbBr-CeBr3-HBr-H2O在25℃时的溶度数据,绘制了相应的溶度图.该四元体系由2个固相区RbBr(原始盐),CeBr3.6H2O(原始盐)组成,是一简单共饱型体系.双饱点组成(平均值)为:HBr 13.34%,CeBr344.15%,RbBr 6.84%.与文献报道的此类氯化物体系比较发现,溴化物体系与氯化物轻稀土体系有较大的相化学关系差异,其原因可能是溴阴离子半径较大所致.

The solubility of saturated solutions of quaternary system RbBr-CeBr3-HBr-H2O at 25 ℃ was determined and the corresponding equilibrium diagram was constructed.The quaternary system is simple with two stable equilibrium solid phases RbBr,and CeBr3·6H2O.The composition of double saturation point（average） is HBr（13.34%）,CeBr3（44.15%）,RbBr（6.84%）.Comparing the reported chloride quaternary systems with the present quaternary system,we find that biggish difference of phase chemical relation is showed for the light earth chloride and bromide quaternary systems with RbCl（or RbBr）.