Cu^(2+)作用下Fenton氧化处理苯酚废水研究

Treatment of Phenol Wastewater by Fenton's Reagent under Cu^(2+) Conditions

[目的]寻找Cu2+存在条件下Fenton氧化处理苯酚模拟废水的最佳条件。[方法]研究不同浓度H2O2、Fe2+及pH下Cu2+的存在对Fenton氧化处理苯酚模拟废水的苯酚去除率的影响和对COD降解效果的影响。[结果]在苯酚浓度为250 mg/L,最佳pH为3.0,H2O2浓度为297.5 mg/L,Fe2+浓度为140 mg/L时,苯酚的最高去除率为94.5%;在此条件下,Cu2+浓度为40 mg/L时,苯酚最高去除率为97.7%,提高了3.2%。在pH3.0、Cu2+浓度40 mg/L条件下,分别求得不同Fe2+/H2O2下的模型条件参数,结果表明Fenton氧化降解苯酚废水符合二级降解动力学反应模型。[结论]适当浓度的Cu2+可提高Fenton氧化降解苯酚废水的效率。Fenton氧化降解苯酚废水符合二级降解动力学反应模型。

[Objective] The aim of the study was to seek an optuim appropriate factors for treating oxidizing phenol wastewater by Fenton＇s reagent under the existing Cu2＋.[Method] The effect of Cu2＋ on removal rate of oxidizing phenol and the effect of degratation of COD by Fenton＇s reagent under different concentrations Fe2＋,H2O2 and pH were studied.[Result] 94.5% phenol could be removed from the wastewater when the optimum pH value 3.0,H2O2 concentration 297.5 mg/L,Fe2＋ concentration 140 mg/L were applied.Above the conditions,phenol removal rate could be reach 97.7% when 40 mg/L Cu2＋ was added,increasing by 3.2 %.When the optimum pH value was 3.0,and Cu2＋ was 40 mg/L,the model parameters at different Fe2＋/H2O2 ratios were calculated,it showed that the process fitted two-step kinetic model.[Conclusion] The appropriate Cu2＋ could improve the degradation efficiency of phenol in the wastewater.The Fenton＇process fitted two-step kinetic model