三个素数猜想的证明

Proof of the conjecture of three prime numbers

采用新的构造方法,把不规则分布的素数进行分类,即把单个素数a都同时表示成等距的区间[a,a+h](a为任意素数),在[a,a+h]中的元素为自然数,将[a,a+h]中对应位置有相同情况,或都是素数,或都不是素数的为同一等价类,其中每个[a,a+h]中至少有一个素数a,h取不同自然数时,分类方法不同,显然[a,a+h]的等价类的个数在h有限时是有限的,小于2h/2。

A new construction method is adopted to classify the irregular distribution of prime numbers.A single prime number is expressed at the same interval [a,a ＋ h],（a is an arbitrary prime number） and the elements in the interval are the natural number.Corresponding elements in the interval [a,a ＋ h],be they prime or not prime,belong to the equivalence class.Each [a,a ＋ h] at least has one prime number.When the letters a,h take different natural numbers,the classification is different.Then we can conclude that when h is limited,the number of the equivalence is limited and less than 2h/2.