期刊文献+

基于双阈值非线性导数的边缘检测算子 被引量:1

Edge Detection Operator Bsaed on the Dual-Threshold Nonlinear Derivative
下载PDF
导出
摘要 文中提出了一种基于双阈值非线性导数算子的边缘检测方法.首先计算灰度图像的左右导数,然后通过设置双阈值对左右导数进行调整以保留有意义的边缘信息,最后合并左右导数得到图像梯度.阈值能控制平滑噪声能力,阈值能确保检测出单像素宽度的线边缘,而非线性导数计划可解决定位错位性的问题.实验结果表明,同传统的离散梯度算子相比,此算子不仅计算简单灵活,检测精度高,而且在没有平滑图像噪声的情况下得到了良好的边缘图像和信噪比. This article presents a edge detection method,which is based on the dual-threshold nonlinear derivative operator.Firstly,gray image is used to calculate the right and left derivative.Secondly,dual-threshold is used to injust the right and left derivative to remain the meaning edge information.At last,the two derivatives are merged to get the image gradient.can control the ability of reducing noise;can ensure detection of the one pixel width edge lines;and the nonlinear derivative scheme can solve the problem of delocalization.By comparing and analying it with the traditional discrete gradient operators in the experimental demonstrations,we find that this operator is not only with advantages of sinplicity,higer accuracy of detection,but also get better edge image and higer SNR in the case of no any smootning.
出处 《微电子学与计算机》 CSCD 北大核心 2011年第7期113-116,共4页 Microelectronics & Computer
关键词 边缘检测 边缘定位 噪声图像 左右导数 双阈值 非线性导数 edge detection edge localization noise image right and left derivative dual-threshold nonlinear derivative
  • 相关文献

参考文献4

  • 1J Canny. A computational approach to edge detection [J]. IEEE Trans Pattern Analysis and Machine Intelli- gence,1986,8(6):679-698.
  • 2Parker J R. Algorithms for image processing and com- puter vision [M]. [ S. L. ]: John Wiley and Sons, Inc, 1997.
  • 3Laligant O, Truchetet F. A nonlinear derivative scheme applied to edge detection[J]. IEEE Trans on Pattern A- nalysis and Machine Intelligence, 2010, 32 (2) : 242-257.
  • 4K Chen. Adaptative smoothing via contextual and local discontinuities[J]. IEEE Trans on Pattern Analysis and Machine Intelligence, 2006,27(10) 1552-1567.

同被引文献7

引证文献1

二级引证文献15

相关作者

内容加载中请稍等...

相关机构

内容加载中请稍等...

相关主题

内容加载中请稍等...

浏览历史

内容加载中请稍等...
;
使用帮助 返回顶部