摘要
本文主要讨论了非常数整函数f(z)与其导数分担两对值的情形,得到了一个结果.
In this paper, the following theorem has been proved :if f(z) is nonconstant entire funetion, and {a1-b1}f'(z)-(a2-b2)f(z)-(a1b2-a2b1)=0.or f (z)-f''(z)=b1-a1=b2-a2 = constant
出处
《新疆师范大学学报(自然科学版)》
1997年第2期1-3,共3页
Journal of Xinjiang Normal University(Natural Sciences Edition)
关键词
整函数
分担值
entire function, share value