关于连续数方程一个结果

one Results of the Diophantine Eqation in Continuous Integer

本文用初等方法证明了;当n,r为正整数s为非负整数,丢番图方程sum from n=0 to n-1 [1+(40s+17)k]~r=[1+(40s+17)

The following results have been proved: Iet n.r be positire integer, s be nonnegatire integer the eguation [l+(40s + 17)k]r = [l+(40s + 17)n]r has on integer solution