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丢番图方程3~n+px^2=y^p(英文)

The Diophantine Equation 3~n+px^2=y^p
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摘要 讨论了丢番图方程3n+px2=yp(x,y,n∈N;p是奇素数)的可解性,得到以下结果:(1)当p=3时,方程的所有解为(x,y,n)=(46.33t+1,13.32t+1,6t+7),(10.33t+1,7.32t+1,6t+8).(2)当p≡1(mod 24)时,方程没有解. The solvability of Diophanine equation 3n+px2=y^p was investigated in this paper. If p =3, the equation has only solution (x,y,n)=(46·3^3t+1,13·3^2t+1,6t+7),(10·3^3t+1,7·3^2t+1,6t+8).If p =1 (mod 24), then the equation has no solution.
作者 潘家宇
出处 《河南科学》 2011年第12期1416-1420,共5页 Henan Science
基金 Research Project of Henan University of Technology(2006XJC038)
关键词 丢番图方程 二次数域 类数 Diophanine equation quadratic number field class number
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参考文献8

  • 1Cao Zhenfu. On the Diophantine equation x^p-y^p=Dz^2 (Chinese) [J]. J Northeast Math, 1986 (2):219-227.
  • 2Cao Zhenfu. Introduction to Diophantine equations (Chinese) [M]. Harbin: Harbin Institute of Technology Press, 1989.
  • 3Le Maohua. On the Diophantine equation 2^n-px^2=y^p[J]. Proe Amer Math Soe, 1995 (123):321-326.
  • 4Le Maohua. Some exponential Diophantine equations I. The equation D1x^2 -D2y^2 =Ak^z [J]. Journal of Number Theory, 1995 (55) : 209-221.
  • 5Le Maohua. Applications of the Gel' fond-Baker method to Diophantine equations (Chinese) rM]. Beijing: Science Press, 1998.
  • 6Nagell T. Sur I'impossbilite de quelques equations a deux indetrminess [J]. Norsk Mat Forenings Skr, 1923 (13):65-82.
  • 7Ribenboim P. The little book of big prime [M]. New York: Springer-Verlag, 1991.
  • 8Robinowitz S. The solutions of 3y^2 ±2^n =x^2 [J]. Proc Amer Math Soc, 1978 (69) : 213-218.

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