摘要
在140℃的条件下,用KMnO4分别与甲醇、乙醇、丙醇、丁醇、乙二醇、1,3-丙二醇以及1,4-丁二醇进行水热反应24 h。采用X射线粉末衍射(XRD)与环境扫描电子显微镜(SEM)对反应产物进行表征。结果表明,KMnO4与乙醇、丙醇、丁醇以及1,4-丁二醇反应均可以得到较纯的棒状MnOOH晶体。KMnO4与甲醇、1,3-丙二醇反应不仅得到了MnOOH晶体并且也得到Mn3O4晶体,而与乙二醇的反应只得到了Mn3O4晶体。并简单探讨了形成这种规律的原因。
KMnO4 reacts with methanol,ethanol,1-propanol,1-butanol,glycol,1,3-propandiol and 1,4-butandiol for 24 h respectively at 140 ℃ via hydrothermal method.The product was characterized by X-ray powder diffraction and scanning electron microscopy.The result showed that when KMnO4 reacts with ethanol,1-propanol,1-butanol and 1,4-butandiol respectively,the products are rod-like MnOOH crystal,and when KMnO4 reacts with methanol and 1,3-propandiol respectively,the products are MnOOH crystal and Mn3O4 crystal,and when KMnO4 reacts with glycol,the products are Mn3O4.Furthermore,the cause of the result was briefly discussed.
出处
《人工晶体学报》
EI
CAS
CSCD
北大核心
2012年第3期652-655,共4页
Journal of Synthetic Crystals