摘要
对任意正整数n,著名的Smarandache函数S(n)定义为最小的正整数m,使得n│m!.对于任意给定的正整数n,伪Smarandache函数Z(n)定义为最小的正整数m,使得n│1+2+…m=m(m+1)/2.对任意正整数n,伪Smarandache无平方因子函数Zw(n)定义为最小的正整数m,满足n│mn,即Zw(n)=min{m∶m∈N,n│mn}.用初等方法研究了方程S(n)+Z(n)=n和Zw(Z(n))-Z(Zw(n))=0并给出了它们的全部解.
For any positive integer n, the famous Smarandache function S (n) is defined as the smallest positive integer m such that n I m I . The Pseudo-Smarandache function Z(n) is defined to be the smallest positive integer m such that n│1+2+…m=m(m+1)/2. The Pseudo-Smarandache function Zw (n) is defined to be the smallest positive integer m such that n│mn. The main purpose of this paper is to use the elementary method to study the equation S(n)+Z(n)=n和Zw(Z(n))-Z(Zw(n))=0 and all solutions for them are given.
出处
《河南科学》
2013年第1期21-24,共4页
Henan Science
基金
渭南师范学院重点科研计划项目(11YKF016)