黑鲷的胃排空率

Gastric evacuation rate of black sea bream(Sparus macrocephalus)

在实验室内 ,18℃条件下测量了体重在 2 0～ 40g的黑鲷的胃排空率 ,并用 3种数学模型拟合了黑鲷的排空率 .结果表明 ,3种模型都能很好地拟合实验数据 ,但通过统计学分析发现不论是用湿重还是用干重表示胃含物 ,线性模型都拟合得最好 .用湿重表示时模型为Y =1 14 -0 0 6t(r2 =0 82 ,p <0 0 0 1) ;而用干重表示时模型为Y =1 3 6-0 0 7t(r2 =0 62 ,p <0 0 0 1) .实验还得出体重 2 0～ 40g的黑鲷在 18℃的胃排空率为每小时排出摄入食物量的 6%～ 7% .

The gastric evacuation rate of black sea bream( Sparus macrocephalus )weighing 20～40g was determined at 18℃ in laboratory.Three mathematical models were applied to simulate it.The result indicated that all of these three kinds of models fitted to the experiment data,while statistical analysis showed that the linear model was the best,whether the remained food in stomach was expressed by wet weight or dry weight.When the remained food in stomach was expressed by wet weight ,the model was Y=1 14-0 06t(r 2=0 82,p< 0 001),and by dry weight,it was Y=1 36-0 07t(r 2=0 62,p <0 001).The gastric evacuation rate of black sea bream was 6～7% of consumed food per hour at 18℃.