摘要
在氯化钠存在下,正丙醇水溶液能够分为醇/水两相,在分相过程中,SbCl6-与罗丹明B(RhB)生成的[SbCl6-][RhB+]三元缔合物能被正丙醇相完全萃取。使Sb5+与Ru3+、Ag+、Cr3+、Cu2+、Mg2+、Fe3+、Ni 2+和Co2+完全分离。该法在微量锑的分离和富集分析中有一定的实用价值。
1-Propanol aqueous solution could be well divided into 1-propanol/water two phases in the presence of sodium chloride.The ternary complex [SbCl-6] formed with SbCl-6 and Rhodamine B could be completely extracted during this process.Sb5+ could be quantiatively separated from Ru^3+,Ag^+,Cr^3+,Cu^2+,Mg^2+,Fe^3+,Ni^2+ and Co^2+ by extraction.This method is practicable in separation and enrichment analysis of trace antimony.
出处
《化学世界》
CAS
CSCD
北大核心
2013年第5期276-278,共3页
Chemical World
基金
河南省教育厅自然科学研究计划项目(2006150023)
关键词
锑
罗丹明B
正丙醇
萃取分离
antimony
Rhodamine B
1-propanol
extraction separation