摘要
以偶氮二异丁腈为引发剂,六水合三氯化铁为催化剂,六次甲基四胺为配体,维生素C为还原剂,通过原子转移自由基聚合合成了苯乙烯/丙烯酰胺共聚物。研究了反应工艺条件对苯乙烯/丙烯的共胺共聚合的影响。并用傅里叶变换红外光谱仪对聚合产物进行了表征。结果表明,采用该方法合成苯乙烯/丙烯酰胺共聚物的最佳工艺条件为:反应温度为90℃,反应时间为2 h,引发剂偶氮二异丁腈用量为两个单体物质的量总和的3.5%,还原剂维生素C用量为两个单体物质的量总和的1.5%,配体六次甲基四胺用量为两个单体物质的量总和的1.25%,单体苯乙烯与丙烯酰胺摩尔比为7∶3。
In this study, azobisisobutyronitrile as an initiator, ferric chloride hexahydrate as a catalyst, hexamethylenetetramine as a ligand, vitamin C as a reducing agent, styrene/acrylamide copolymers were synthesized by atom transfer radical polymerization (ATRP). The effects of reaction paramefers on the polymerization were investigated. The copolymer was characterized by Fourier transform-infrared spectroscopy. Experimental results showed that, with this method, the optimum conditions for the reaction temperature was 90 ~C, the reaction time for 2 h; the amount of initiator agent was 3.5% of total molars of two monomers, the vitamin C was 1.5% of the total ones, the hexamethylenetetramine was 1.25% of total ones, the monomer ratio of n(styrene)/n(acrylamide) = 7:3.
出处
《石化技术》
CAS
2013年第3期5-7,12,共4页
Petrochemical Industry Technology