摘要
探究药桑色素对X-射线辐射斑马鱼胚胎损伤的保护作用和体外抗氧化能力。方法:用不同浓度药桑色素处理正常发育4h(4hpf)的胚胎,3h后用X-射线(辐射强度20Gy)一次性照射,分别测定胚胎的ROS、MDA和SOD值;采用DPPH和ABTS的方法测定药桑色素的抗氧化能力。结果:与对照组和辐射组(20G)相比较,在0.5μg/mL、5μg/mL和50μg/mL组中,ROS生成量表现差异极显著(P<0.01);SOD活性表现差异不显著(P>0.05);与对照组相比较,MDA含量在5μg/mL组中表现差异极显著(p<0.01),在50μg/mL组中表现差异显著(P<0.05);与辐射组(20G)相比,MDA含量在5μg/mL和50μg/mL组中表现差异极显著(p<0.01)。结论:药桑色素对斑马鱼胚胎的损伤具有保护作用,其机制可能与药桑色素提高斑马鱼胚SOD活性,减少氧自由基的产生,抑制脂质过氧化有关。药桑色素也具有较强的清除自由基能力。
Investigate the anti-irradiation effect of Morus nigra L.pigment on zebrafish embryo.Methods 4h post fertilization zebrafish embryos were treated with various concentrations(0.5,5,50ug / mL) Morus nigra L.pigment.Three hours later,x-ray(20Gy) was applied.Then the level of ROS in zebrafish embryo was determined by ROS probe(2,7-dichloro fluorescein diactate,DCFH-DA),and the content of superoxide dismutase(SOD) and malondialdehyde(MDA) in the zebrafish embryo tissue were evaluated by biochemical method assay.Results compared with the control and irradiation group,ROS content was significantly different(p &lt; 0.01) with different concentration of pigment;The activity of SOD was not obvious increased(P &gt; 0.05);In 5 and 50μg / mL groups,the content of MDA reduced with the increase of pigment concentration and was significantly lower compared with the control gropu(p &lt; 0.01).Conclusion Morus nigra L.pigment had radiation protection ability of zebrafish embryos,the mechanism may due to the improvement the SOD activity,reducing oxygen free radicals and inhibiting the lipid peroxidation.The test also showed that Morus nigra L.pigment had anti-oxidative activity.
出处
《中国食品添加剂》
CAS
北大核心
2013年第4期103-106,共4页
China Food Additives
关键词
药桑色素
辐射保护
斑马鱼胚胎
抗氧化
morus nigra L.pigment
radiation protection
zebrafish embryo
anti-oxy