关于丢番图方程x^3+1=301y^2

On the Diophantine Equation x^3+1=301y^2

鲁伟阳等人利用递归数列,同余式、平方剩余以及Pell方程的解的性质证明了不定方程x3-1=301y2仅有整数解(x,y)=(1,0).该文给出方程x3+1=301y2的解.

Weiyang Ru ,et al .use recurrent sequence ,congruence ,quadratic remainder and some properties of the solutions to Pell equation to prove that the Diophantine equation x3 -1=301 y2 has only integer solution （x ,y）= （1 ,0） .In this paper ,On the Diophantine Equation x3 ＋ 1 = 301y2 ,we give a simple method .