关于丢番图方程x^3±1=3·2~αpD_1y^2

On the Diophantine Equation x^3±1=3·2~αpD_1y^2

设D_1=multiply from i=1 to s q_i(s=1或2),q_i≡-1(mod6)(i=1,2,…,s)是彼此不同的奇素数,p≡1(mod6)为奇素数.运用初等方法讨论了丢番图方程x^3±1=3·2~αpD_1y^2(α=0或1)的正整数解的情况.

D1=Пi=1^s qi（s=1 lor 2）,qi≡-1（mod6）（i=1,2,…,s）are different odd primes. Using the elementary method, we discussed that the positive integer solutions of the Diophantine equationx3 x3±1=3·2^apD1y2.