一个求解非线性方程的2^(1/2)+1阶的迭代公式

Iteration formula to solute nonlinear eqution

给出一个求解非线性方程的迭代公式 ,它是一个二步法计算公式 ,就计算量来看 ,它几乎和Newton法一样 ,但它却具有超平方收敛性 ,其收敛阶为 2 + 1 .

An iteration formula to find root od nonlinear eqution with two step method is presented in this paper.As far as the computional amount on functional evaluation is concerned,like Newton's method ,it is super quadratically convergent,whose order is 2+1.