摘要
利用简洁初等方法证明了Lucas方程x(x + 1) ( 2x + 1) =6y2 仅有正整数解 (x ,y) =( 1,1) ,( 2 4,70 ) ,获得了丢番图方程x(x+ 1) ( 2x + 1) =2py2
We make use elementary theory of number prove Lucas equations x(x+1)(2x+1)=6y 2 positive integer solutions merely are (x,y)=(1,1),(24,70); We also abeain Diophntine equations x(x+1)(2x+1)=2py 2 have Positive integer solutions necessary and sufficiene condition.
出处
《商丘师范学院学报》
CAS
2001年第2期63-65,共3页
Journal of Shangqiu Normal University
基金
广西民族学院重点科研项目资助课题! ( 98SXX0 0 0 0 2 )