某些解析函数的星形半径

The Starlike Radius of Certain Analytic Function

设f(z)=((α+γ)/z~γCintegral from n=1 to z(f(t)^(t(γ-1)dt)))^(1/a)∈S*(ρ),α≥0,γ≥0,1>ρ≥0。本文找到园盘,使f(z)在该圆盘内是l(0≤l<1)级星函数。结果是准确的,推广了[2]的结论。

Let where is starlike radius p in D = {z:|z|<1}. The purpose of this paper is to find out the disc in which f(z} is starlike radius l ,0≤l <1 . The results are exact and extend the conclusion of(2) .