分拆大偶数为两个几乎相等的素数之和

Partitioning Large Even Numbers as the Sums of Two Almost Equal Primes

我们称n =p+q 为偶数n的最平衡哥德巴赫分拆 ,其中 p与 q均为奇素数 ,p≤ q且 |p - q|取可能的最小值。根据哥德巴赫猜想 ,对于每个大于或等于 6的偶数 ,必存在其最平衡哥德巴赫分拆。本文通过对 10 7以内的偶数进行的数值计算 ,进一步提出如下猜想 :由所有 (≥ 6的 )偶数之最平衡哥德巴赫分拆产生的三组比值 p/q ,p/n 以及 (n/2 -p) /n的均值 ,分别具有极限 1,1/2及 0。

We call n=p+q as the most balance Goldbach partition for even number n,where p and q are all odd primes,p≤q and |p-q| takes the possible minimal value.According to the Goldbach's conjecture,there exists the most balance Goldbach partition for every even number greater than or equal to 6.By numerical computation with the even integers not exceeding 10 7,we now propose the following conjecture:the means of quotients p/q,p/n,and (n/2-p)/n defined by the most balance Goldbach partitions of all even numbers(≥6) have the limits 1,1/2,and 0,respectively.