第2类Stirling数Bernoulli数与Euler数的解析表示式

Analytic Representative of Two Class Stirling Number and Bernoulli Number and Euler Number

本文给出第2类Stirling数,Bernoulli数与Euler数的解析表示式: s_2(m+1,n)=(-1)~n/n1 sum form j=1 to n(-1)~j(?)_j^(-m+1) B_n=sum form k=1 to n 1/(k+1) sum form j=1 to k (-1)~j(?)_j^(-n) E_(2n) =1/(2n+1)[sum from p=0 to n-1 sum from k=1 to 2(n-p) sum from j=1 to k (-1)^(j-1)/(k+1)·(?)(?)(4j)~2(n-p)+4n+1]因此解决了它们的计算问题。

This article shows analytic representative of two class Stirling number , Bernoulli number and Euler number Thus their calculation problems have been solved.