摘要
i =1∏(xi+xi≥)(n+n)本文给出了不等式的一种简证,并对其进行了推广,同时提出更进一 步的猜想.
n?i = 1(xi+1xi≥)(n+1n)n:This article simplified demonstrates the inequality , and popularizes it and puts for-ward furthur guess.
出处
《克山师专学报》
2002年第3期29-30,共2页
Journal of Keshan Teachers College