摘要
利用公式△U=-0.1196n/λ计算20℃、0.1MPa、惰性气体处于临界浓度时甲烷爆炸反应形成的温度T2,进而计算了爆炸形成的压力p2.若惰性气体为CO2,则T2=1380K,p2=0.47MPa;若惰性气体为CCl4,则T2=1372K,p2=0.47MPa;若惰性气体为N2,则为T2=1361K,p2=0.46MPa;若惰性气体为Ar,则T2=1354K,p2=0.46MPa;若无惰性气体,甲烷的浓度为爆炸下限,则T2=1341K,p2=0.46MPa.
The temperatures produced by CH4 explosions at 20℃,0. 1MPa are calculated by the formula Δ U = - 0. 1196n/λ when inert gases are at critical concentrations, then the pressures are calculated. If inert gas is CO2, T2 = 1380K,p2 = 0.47 MPa; If inert gas is CCl4, T2 = 1372K ,p2 = 0.47 MPa ; If inert gas is N2, T2 = 1361K,p2 = 0.46MPa; If inert gas is Ar, T2 = 1354K,p2 = 0.46MPa;if CH4 concentration is at the explosion lower limit with no inert gas, T2 = 1314K,p2 = 0.46MPa.
出处
《泰山学院学报》
2015年第3期89-93,共5页
Journal of Taishan University
关键词
爆炸反应
温度
压力
甲烷
explosion reaction
temperature
pressure
methane
