Fe^(2+)/Cu^(2+)/H_2O_2类芬顿体系降解苯酚

The degradation of phenol by Fe^(2+)/Cu^(2+)/H_2O_2 Fenton-like system

研究了Fe^(2+)/Cu^(2+)/H_2O_2类芬顿体系的最佳比例以及苯酚的初始浓度、时间对降解苯酚的影响,使用异丙醇作为羟基自由基淬灭剂研究了芬顿体系降解苯酚的机理。结果表明,处理100 mL100mg/L的苯酚溶液时的最佳条件是H_2O_2(体积分数为30%)为1mmol、硫酸亚铁为0.5mmol、硫酸铜为0.3mmol,反应时间达到60min时,降解率可达到99%;机理研究部分验证了羟基自由基是降解苯酚的主要因素。

The structure of the Fe（Ⅱ）/Cu（Ⅱ）/H2O2 was studied.The effects of initial concentration of phenol and reaction time on the degradation efficiency of phenol were investigated.The isopropyl alcohol was used as the hydroxyl radical quenching agents to study the mechanism of the Fenton-like system.The results showed that the optimum conditions of degrading 100 mL phenol were obtained as follows：H2O2（volume fraction was 30%）was 1 mmol,ferrous sulfate was 0.5 mmol,copper sulfate was 0.3 mmol.When the reaction time was 60 min,the degradation efficiency could reach 99%.Mechanism research verified the hydroxyl radicals were the main factors of degradation of phenol.