环行计数器的自启动问题

How to Solve the Question of the Ring Counter's Self-starting

若一个环行计数器不能自启动 ,选择某一个触发器的输入端作为修改点 ,在卡诺图中将原逻辑化简圈外的约束项修改为 1,而该约束项必须与原逻辑化简圈内的有效状态项 1逻辑相邻 。

If a ring counter does not start on itself, choose an input port of a Flip-Flop, as correct port, in Karnaugh map, modify the constraint term out of the original logical simplified loop into 1, the constraint item must be border upon logic with the efficient state term 1 in the original logical simplified loop, then it can be modified it into a self-starting logical circuit.