摘要
从发散的调和级数∑∞ｎ＝１１ｎ分母ｎ中去掉含有０到９的任意ｄ个（１≤ｄ≤９）数字的项后，剩余项组成的新级数收敛．从每个ｄ的众多新级数中求出最大级数，并提出寻找符合条件的自然数ｎ的方法。
Removing terms whose denominator is contain digits fro
m 0 to 9 altogether d(1≤d≤9)digits arbitrarily from the divergent harmonic ser
i
es∑∞n=11n,the series with its remained terms will be
convergent. In this paper,the maximal series is obtained from numerous new serie
s of every d. The method is presented for seeking natural number n which is mee
t condition and upper bound of corresponding sum is calculated by using computer
at last.
