两步碱催化法合成水溶性酚醛树脂

Synthesis the water soluble phenol-formaldehyde resin by two step alkaline catalytic reaction

以苯酚∶甲醛=1∶3(摩尔)的比例,采用两步碱催化合成工艺,促使苯酚苯环上的邻、对位都能进行羟甲基化反应,在50℃～90℃程序升温下连续反应2小时,经减压脱水后,合成出固含量82%的水溶性甲阶酚醛树脂,残留甲醛量为1.1%(wt),游离酚为0.05%(wt)。

A phenolfromaldehyde resol resin is prepared from phenol and formaldehyde of molar ratio 1∶3 in aqueous solution through a twostep alkaline catalytic reaction at 50℃～90℃ procedurally heating up over 2 hours. After dewatering by decompressing, the concentration of products is 82% and the residue formaldehyde and the phenol in the resin are 1.1%(wt) and 0.05% (wt) respectively.